1G as a Universal Coefficient
Is there any evidence that 1G is not a universal coefficient?
I ask this question because "relativity" requires a point of reference. Einstein says that from the Newtonian base (F=MA), uses the speed of light as the reference point to the relativity of M.
Therefore what would A (acceleration) use as the reference point for relativism?
Would E=A(G squared) make sense as the equivalent to E=M(C squared)?
I am not a mathematician. But I am attempting to say that A and G do not maintain the same fixed relation in space, where G=0.
The weightless trick in the astronaut training aircraft is because:
-1A + 1G = 0G
That is saying that A=G when A is 9.8 M per second squared.
So is A is for examples 98M per second square performing the same trick:
-10A + 1 G = 9G
What if 1G is a universal coefficient? No evidence of life beyond our planet is a good starting point for a universal coefficient. That is to say future evidence of humanoid or intelligent life could in theory be found only to exist on 1G planet. If life is found on non-1G planets, unless it is intelligent enough to have a language to attach meaning to the term “coefficient”, it would not invalidate 1G as a universal coefficient.
In that case, the relationship of E=M(C squared) to F=MA could be the same as E=A(G squared). The substance being that as C (the speed of light) cannot be surpassed no matter how great F is because the increase in M is exponential. Therefore for a "relativity of natural gravity" the G (the natural gravity) cannot be surpassed no matter how great A is because the decrease in F is exponential.
Returning to the example of -10A + 1 G = 9G
In space where G=0 (and true zero is beyond Pluto)
If G=0, then
-10A + 0G=1G
That is to say, no matter how big A is, G will never surpass 1.
1G as a Universal Coefficient continued
This is because what we are observing under 1 G is:
-10A(A(E squared)) + 1G = 9G
In space where G=0, E=A(G squared) or (E squared)=AG or G=A(E squared)
A(E squared)) on earth is 1, that is to say 1G
So -10A(A(E squared)) + 1G = 9G
Because
-10A(1) + 1G = 9G
When G=0
-10A + 0G=1G
Because the true equation is:
-10A(A(E squared)) + 0G=1G
Since E=A(G squared), there is an exponential decrease in F as A increases.
A(E squared) will therefore not remain at the earth constant of 1, but rather decrease exponentially towards 0
So in the example:
-10A(A(E squared)) + 0G=1G
A(E squared)=0.1
Therefore -10A(A(0.1) + 0G=1G
That is to say:
10A(0.1) + 0G=1G
Simplified to 1A+0G=1G
No matter how large A is, A(A(E squared)) + 0G=1G where G=0